10行代码搞定年会抽奖

10行代码搞定年会抽奖

某科技公司有300员工，开年会抽奖，奖项如下：

一等奖	3名
二等奖	6名
三等奖	30名

规则：

1，共抽3次，第一次抽3等奖，第2次抽2等奖，第3次抽1等奖；

2，每个员工限中奖一次，不可重复；

解题思路：

1,生成一个员工列表，用random模块从里面取随机值；

2，取完值之后，立刻从列表中把中奖人删掉，防止其再次中奖。

#年会抽奖程序
import random
staffs = [f"员工-{i}" for i in range(1,301)]    #员工列表
levels = [3,6,30]   #奖项等级人数
count = 3   #3次循环
while c >0:
    choice = input("pree any button to start>>")
    winner = random.sample(staffs,levels[c-1])    #取随机数
    print(f"{c}等奖：",winner)
    for p in winner:     #剔除已经中奖人员
        staffs.remove(p)
    count -=1

运行结果：

pree any button to start>>
3等奖： ['员工-298', '员工-117', '员工-20', '员工-180', '员工-162', '员工-51', '员工-27', '员工-15', '员工-173', '员工-133', '员工-7', '员工-114', '员工-127', '员工-19', '员工-42', '员工-172', '员工-283', '员工-128', '员工-273', '员工-208', '员工-26', '员工-221', '员工-256', '员工-144', '员工-138', '员工-203', '员工-278', '员工-48', '员工-97', '员工-300']
pree any button to start>>
2等奖： ['员工-98', '员工-272', '员工-88', '员工-291', '员工-137', '员工-116']
pree any button to start>>
1等奖： ['员工-53', '员工-238', '员工-25']